The second is to operate the oil-fired boiler (using No. 2 fuel oil) which keeps the radiators warm all night. Electricity costs, excluding demand charges, is 10 cents per kilowatt hour; No. 2 fuel oil costs +n 1.00 per gallon. Assume the boiler is 70% efficient and exclude the costs of running pumps and fans to distribute heat.

Chat OnlineIf the turbine work output is 600 kj/kg, determine: 1 answer m=1.9 kg K =459 N/m Delta =44 mm theta = 27 Degree Find the amount which the spring is compressed after the mass comes to rest. Assume a kinetic coefficient of friction of 0.14 and an initial velocity What is the amount of heat required to convert this into saturated water?

Chat Online2.4 Problem 4: 12.97 Consider an ideal air-standard Stirling cycle with an idealregenerator. The minimum pressure and tmeperature in the cycle are 100 kPa, 25 C, the compression ratio is 11, and the maximum temperature in the cycle is 1000 C. Analyze each of the four processes in this cycle for work and heat transfer, and determine the overall perfomance of the engine.

Chat OnlineW = boiler capacity (Btu/h, kW) h g = enthalpy steam (Btu/lb, kJ/kg) h f = enthalpy condensate (Btu/lb, kJ/kg) m = steam evaporated (lb/h, kg/s) Boiler Horsepower - BHP. The Boiler Horsepower (BHP) is. the amount of energy required to produce 34.5 pounds of steam per hour at a pressure and temperature of 0 Psig and 212 o F, with feedwater at 0

Chat OnlineConvert your units of hp into pounds of steam per hour by multiplying the number calculated in the previous step by 34.5. Using numbers from our previous example, if you multiply 220 by 34.5, then you get 7,590 pounds of steam per hour created by your boiler (220 x 34.5 = 7,590).

Chat OnlineSteam Required (lbs / hr) lbs / hr = Btu per hour Enthalpy of Steam at Operating Pressure lbs/hr = Btu/hr Btu/lb F s or Btu / lb oF F s = Horse Power to be Removed x 2545 x Correction Viscosity (Oil Leaving oF - Ambient Air Entering oF) F s = HP x 2545 x Cv T 2 - t a 8 Conversions and Formulas To Convert Into Multiply By

Chat OnlineCalculate the kilowatt-hours (kWh) required to heat the water using the following formula: Pt = (4.2 × L × T ) ÷ 3600. Pt is the power used to heat the water, in kWh. L is the number of liters of water that is being heated and T is the difference in temperature from what you started with, listed in degrees Celsius.

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Chat OnlineIsobaric heat addition (in a heat exchanger - boiler) - In this phase (between state 2 and state 3) there is a constant-pressure heat transfer to the liquid condensate from an external source, since the chamber is open to flow in and out. The feedwater (secondary circuit) is heated from to the boiling point (2 → 3a) of that fluid and then

Chat OnlineNow divide condensate removal (or steam consumption) per hour and divide the same with 60 (to convert hours to minutes) and then with yankee RPM. Condensate Removal per Rotation of Yankee • For a typical case, steam consumption was 3000 kg/Hr. Machine speed was 210mpm and yankee circumference was 13.3M. • So the condensate removal per

Chat OnlineThe volumetric flow rate in a heating system can be expressed as. q = h / (c p ρ dt) (1). where. q = volumetric flow rate (m 3 /s). h = heat flow rate (kJ/s, kW). c p = specific heat (kJ/kg o C). ρ = density (kg/m 3). dt = temperature difference (o C). This generic equation can be modified for the actual units - SI or imperial - and the liquids in use.

Chat OnlineThe heat input required by the boiler to produce the required steam is only 1,149.1 Btu/lbm (1,474.1 325.0), while the feedwater temperature is much warmer. Thus, the efficiency of this system is

Chat Online1) Calculate the ideal efficiency of a heat engine that takes in energy at 800 K and expels heat to a reservoir at 300 K. (800 K-300 K)/(800 K)= o.63 2) Calculate the ideal efficiency of a ship's boiler when steam comes out at 530 K, pushes through a steam turbine, and exits into a condenser that is kept at 390 K by circulating seawater.

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Chat OnlineOften it is necessary to convert a measure of capacity from one term to another. The conversion table will allow you to quickly convert various measures of capacity. The table and formulas can help you size and pick out components such as condensate pumps and boiler feed pumps. Some additional conversion factors that may prove helpful are shown below.

Chat OnlineTo heat the same water volume in half the time (30 minutes) would need twice the heating power, ie, 7kW. Converesely, if we only use half the heating power, 1.75kW, it will take twice as long to heat up to desired temperature, ie, 2 hours. If we only have a 1kW element available, we will expect a heat up time in excess of 3 hours.

Chat OnlineOnline calculator with Saturated Steam Table by Pressure. Includes 53 different calculations. Equations displayed for easy reference.

Chat OnlineSteam, Boiler, and Blowdown Pressure are the same. Combustion Efficiency is the % of fuel energy that is directly added to the feedwater and not otherwise lost or used. Blowdown Rate is the % of incoming feedwater mass flow rate that leaves the boiler as a saturated liquid at boiler pressure.

Chat OnlineA boiler generates 8 kg of dry saturated steam per kg of fuel oil burned. Fuel oil heating value is 33 000 kJ/kg. Feedwater is supplied at 70°C, and the boiler pressure is 1400 kPa. Calculate the boiler efficiency. 57.3% 60.5% 74.7% 85.0% 92.3%

Chat OnlineDiferent flow rate units conversion from pound (water mass) per hour to gallons US per minute. Between lb/h and gal/min measurements conversion chart page. Convert 1 lb/h into gallon US per minute and pounds (water mass) per hour to gal/min. The other way around, how many gallons US per minute - gal/min are in one pound (water mass) per hour - lb/h unit?

Chat OnlineTypically boilers of much size would have a steam meter that calculates flow. This is typically a sensor measuring the pressure drop across and orifice. If you don't have that, then you have two options. Option one is mainly for firetube style boi

Chat OnlineWork done on system = 1.435 kJ Ans. 2. A gas at 65 kPa, 200C is heated in a closed, rigid vessel till it reaches to 4 00C. Determine the amount of heat required for 0.5 kg of this gas if internal energy at 200C and 400C are 26.6 kJ/kg and 37.8 kJ/kg respectively. Solution: Q = ? Given m = 0.5 kg u1 = 26.6 kJ/kg u2 = 37.8 kJ/kg

Chat OnlineIf your boiler supplies 400 pounds of steam per hour, for example, you would multiply 400 pounds by 1,194 to arrive at a figure of 477,600 BTUs. From there you'd need to calculate how best to distribute that heating potential throughout your structure, which involves a different set of calculations.

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